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3x^2-60x=-257
We move all terms to the left:
3x^2-60x-(-257)=0
We add all the numbers together, and all the variables
3x^2-60x+257=0
a = 3; b = -60; c = +257;
Δ = b2-4ac
Δ = -602-4·3·257
Δ = 516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{516}=\sqrt{4*129}=\sqrt{4}*\sqrt{129}=2\sqrt{129}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-2\sqrt{129}}{2*3}=\frac{60-2\sqrt{129}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+2\sqrt{129}}{2*3}=\frac{60+2\sqrt{129}}{6} $
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